a man of mass 40 kg is standing on a weighing machine kept on the floor of an elevator. if the supporting cable breaks,find the reading of the weighing machine
Answers
Answered by
5
Ans is 0 as in case of free fall acceraltion of a body is equal to gravitational acc so as =0
the reading becomes m(g-a) or m(g-g) =0
the reading becomes m(g-a) or m(g-g) =0
Answered by
6
Heya user !!!
Here's the answer you are looking for
⏩When the supporting cable breaks, the lift is having a free fall. So, the lift provides no normal reaction to the man and hence the weight of the person becomes 0.
⏩ Mathematically, when lift is moving down with an acceleration a then weight is m(g - a).
In this case, a = g (as it is having free fall)
So, W = m(g - g) = m × 0 = 0
So, weight is zero.
Therefore, the reading of the weighing machine is zero.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
⏩When the supporting cable breaks, the lift is having a free fall. So, the lift provides no normal reaction to the man and hence the weight of the person becomes 0.
⏩ Mathematically, when lift is moving down with an acceleration a then weight is m(g - a).
In this case, a = g (as it is having free fall)
So, W = m(g - g) = m × 0 = 0
So, weight is zero.
Therefore, the reading of the weighing machine is zero.
★★ HOPE THAT HELPS ☺️ ★★
Similar questions