Question

A man brought 11 oranges and sold 10 at the same rate.
What is his gain percent?

Answer 1

Solution :

A man bought 11 oranges and sold 10 at the same rate.

Let us assume that he bought 11 oranges at a cost of rs. X

Then the cost of one orange :

> ( x/11)

Now , he sold them at the same rate.

So , he sold 10 oranges for rs. X

Hence , selling price of one orange :

> ( x/10)

Selling price > Cost price hence he makes a profit.

Profit margin :

> Selling price - Cost Price

> x/10 - x/11

> x/110

Profit percentage :

> [ x/100] × [11/x] × 100%

> 11%

Thus his gain percent is 11% . This is the required answer.

___________________________

Answer 2

Hiii...

Here is your answer...

Solution:-

CP of 11 oranges are₹10

So,CP of 1 orange=

$= > \frac{10}{11}=>$

• SP of 10 oranges are ₹11
• So,SP of 1 orange=

$\tt = > \frac{11}{10}$

Since,

$\tt\frac{11}{10} > \frac{10}{11}$

SP>CP

So,

Gain=SP-CP

$\tt\frac{121 - 100}{110}$

Now,

$\tt gain\% = \frac{gain}{cp} \times 100gain%$

$\large\tt= > \frac{ \frac{21}{110} }{ \frac{10}{11} }\times 100$

$\tt= >\frac{21}{110}\times\frac{11}{10}\times 100$

• = > 21=>21

Hence,he gain 21℅

• $\bullet\sf{\blue{\underbrace{\underline{\orange{HENCE\; VERIFIED✓}}}}}$