A man buys a plot of land at 360000. He sells one third of the plot at a loss of 20 percentage. Again, he sells tow-thirds of the plot left at a profit of 25percentage. At what price should he sells the remaining plot in order to get a profit of 10percentage on the whole?
Answers
Target sale value to achieve 10% profit on the whole plot = 360000 + (360000 x 0.1) = Rs 396000 (T)
Cost of 1/3 plot = 360000 ÷ 3 = Rs 120000 (c1)
Cost of 2/3 plot = 360000 - 120000 = Rs 240000
Cost of 2/3 plot of 2/3 (plot left after selling 1/3 plot) = 240000 x (2 ÷ 3) = Rs 160000 (c2)
20% loss amount on sale of 1/3 plot = 120000 x 0.2 = Rs 24000
Sale price of 1/3 plot = a - 24000 = Rs 96000 (s1)
Remaining plot is 2/3
Man sells 2/3 of this 2/3 plot at a profit of 25% = 160000 x 0.25 = Rs 40000
Sale price of 2/3 of 2/3 plot = 160000 + 40000 = Rs 200000 (s2)
Total sale value realized so far R = s1 + s2 = 96000 + 200000 = Rs 296000
Target sale value to achieve 10% profit on the whole plot = S (calculated above)
∴ Required sale price for the remaining plot = S - R
= 396000 - 296000
= Rs 100000
The last part of the land should be sold at 150000rs
The total price of the land is 360000.
For the first 1/3 part he should get
x 360000= 120000rs.
But he sells it at a loss of 20%
The amount of loss is →
x120000= 24000rs
Therefore, the amount at which the farmer sold 1/3 of land is →
120000-24000= 96000
Similarly, the next 1/3 of the land was sold at ab amount of
120000+ 25%.
profit(amount)=120000 + 30000=150000rs
To get a total profit of 10% the amount at which the total land should be sold is →
360000+10%profit(amount)= 360000+36000=396000
So the total amount at which he should sell all the three parts should be 396000rs
Therefore,96000+150000+x=396000
Therefore,96000+150000+x=396000
(here x is equal to the amount at which the last 1/3 part of the land should be sold)
Now, 246000+x=396000
. x= 396000-246000= 150000rs.
Therefore the last part of the land should be sold at 150000rs