a man divided his property among his 3 sons amd wife and gave 1/5th of the whole to his first son, 1/3rd of the remaining to his second son and the 3/8 of the remaining to his third son and the rest amount which is Rs12000 to his wife, so what is the value of property?
Answers
Answer:
So right answer is ₹ 130909.09
Step-by-step explanation:
Money given by father to 1st son = 1/5th of total
Money given by father to 2nd son = 1/3rd
Money given by father to 3rd son = 3/8th
Money given by father to wife = ₹12000
Let the total amount be x
A.T.Q
x - (1/5x + 1/3x + 3/8x) = 12000
x - (24x + 40x + 45x /120) = 12000
x - 109x /120 = 12000
120x - 109x /120 = 12000
11x /120 = 12000
x = 12000 × 120 /11
x = 130909.09
So, value of land is ₹ 130909.09
Answer:
Total amount of property is 144000/11 rupees.
Step-by-step explanation:
Let the total property be x.
Given :–
There are 3 sons and 1 wife among whom the property is to be distributed.
Amount of property given to eldest son =1x/5
Amount given to second son=1x/3
Amount given to third son=3x/8
Total amount given to all the three sons
=[1x/5+1x/3+3x/8]
=[ 109x/120]
Amount left for wife
=( total amount - sum of amount of 3 sons)
=(x-109x/120)
=(11x/120)
Now, given amount of wife is 1, 200 rupees.
Therefore on solving,
11x/120=1200
x=1200*120/11
=144000/11
Amount with elder son
=1/5*144000/11
=28800/11 rupees
Amount with second son
=1/3*144000/11
=48000/11 rupees
Amount with third son
=3/8*144000/11
=54000/11 rupees
Total amount:
=28800/11+48000/11+54000/11+1200
=130800/11+1200
=130800+13200/11
=144000/11 rupees.