A man from A to B at rate 4km he had moved at the rate of 8/3 km an hour he would have taken 3 hour more that the distance. find distance of A and B
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let the distance between Aand B be D km
and time taken when he moves with speed 3kmper hour is T
so D=4T
again in the second case
D=(T+3)×11/3
from these two equations we get
11T+33=12T
T=33 hr
now D=4×33
=132km
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