Question

A man goes 1.2 km due north and then 0.5 km due west.Find the least distance between his initial and final positions.
(Pythagoras theorem)plz fast

Answer 1

1.2 km=1200 m
0.5 km=500 m
see the pic

bc²=ab²+ac²
     =(1200)²+(500)²
     =1440000+250000
bc²=1690000
bc=√1690000=1300 m
bc=1.3 km

Answer 2

1300 m/1.3 km (due North-west)