A man goes 1.2 km due north and then 0.5 km due west.Find the least distance between his initial and final positions.
(Pythagoras theorem)plz fast
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Answered by
3
1.2 km=1200 m
0.5 km=500 m
see the pic
bc²=ab²+ac²
=(1200)²+(500)²
=1440000+250000
bc²=1690000
bc=√1690000=1300 m
bc=1.3 km
0.5 km=500 m
see the pic
bc²=ab²+ac²
=(1200)²+(500)²
=1440000+250000
bc²=1690000
bc=√1690000=1300 m
bc=1.3 km
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Answered by
0
1300 m/1.3 km (due North-west)
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