Question

A man goes 30 km due north and then 40 km due east. how far away from his initial position?

Answer 1

30 km upward then 40 km right. This forming a right triangle. Hupotenuse or distance=
H^2= B^2+P^2
H^2= 30^2+40^2
H^2= 900km^2+1600km^2
H^2= 2500km^2
$h = \sqrt{2500 {km}^{2} }$
Hypotenuse= 50km
Hope it helps☺

Answer 2

30 km upward then 40 km right. This forming a right triangle. Hypotenuse or distance is the displacement.

H^2= B^2+P^2

H^2= 30^2+40^2

H^2= 900km^2+1600km^2

H^2= 2500km^2

h = squareroot{2500 {km}^{2} }  

Hypotenuse= 50km