Question

A man had some milk. When he sold 3/4 parts of the quantity of milk, 15 / was left. How much milk did he have in the beginning? could you please explain step by step

Answer 1

Answer:

60 litres

Step-by-step explanation:

Given:

• $\frac{3}{4}$ of the total milk was sold
• after $\frac{3}{4}$ of the total milk is sold 15 litres arre left out

To find:

• How much milk he had in the beginning

Left out milk = 1-$\frac{3}{4}$

Left out milk = $\frac{4}{4} - \frac{3}{4}$

Left out milk = $\frac{1}{4}$

Let the total milk be equal to X

so,

$\frac{1}{4} X = 15$

X=15×4

X=60 litres

He had 60 litres of milk at the beginning

Answer 2

• Given -

• 3/4 milk has been sold
• after selling 3/4 milk, 15 litres is left

• To Find -

• How much milk he had in beginning (Total)

• Solution -

First of all, let's convert left out of milk in it's original form i.e (Simplifying)

$⟹left \: milk = 1 - \frac{3}{4}$

(Here, 3/4 is compared to 1)

$⟹left \: milk = \frac{4}{4} - \frac{3}{4}.. (Cross Multiplying)$

$⟹left \: milk = \frac{1}{4}.. (Common Denominator)$

Now! let's suppose total milk in beginning be x

So, It will be,

$⟹ \frac{1}{4} x = 15$

$⟹x = 15 \times 4.. (Transferring Values)$

$\huge\boxed{x = 60}$

⛬ Total Milk in beginning was 60 litres