A man had two acid solutions one 90% pure and other 97% pure.How many litres of each should be mixed to get 42 litres of 95% pure solution.
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X = no of litres of soln 1
Y = no of litres of soln 2
X + y = 42 -------- (a)
90/100(x) + 97/100(y) = 95/100(42)
90x + 97y = 3990 ------- (b)
Solving (a) and (b)
Y = 30
X = 42 - 30 = 12
Y = no of litres of soln 2
X + y = 42 -------- (a)
90/100(x) + 97/100(y) = 95/100(42)
90x + 97y = 3990 ------- (b)
Solving (a) and (b)
Y = 30
X = 42 - 30 = 12
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