Question

a man has only 20 paisa coins and 25 paisa coins. If he has 50 coins in all, which total up-to rupees 11.25 , how many coins of each kind does he have?

Answer 1

Answer:

25

Step-by-step explanation:

Let no. of 20 paise coins is x and no. of 25 paise coins is y. Then by the given question,

x+y=50 --------------------(1) and

20x+25y=1125 [∵, Rs. 11.25=1125 paise]

or, 4x+5y=225 -----------(2)

Multiplying (1) with 4 we get,

4x+4y=200 ---------------(3)

Subtracting (3) from (2) we get,

y=25

Putting in (1)

x=50-y=50-25=25

∴, x=25, y=25

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Answer 2

$\bold \color{green} { \underline { \underline \red{ \green\star \: required \: answer}}} \star$

Let the number of 20 paisa coins be x and that of 25 paisa coins be y. then,

$\bold{x + y = 50}$

total value of 20 paisa coins = 20x paisa

total value of 25 paisa coins = 25y paisa

$\bold{so \: that \: \: 20x + 25y = 1125 }\\ \bold{ \implies4x + 5y - 225 = 0}$

now by using corss-multiplication, we have

$\bold{\frac{x}{ - 225 + 150} = \frac{ - y}{ - 225 + 20} = \frac{1}{5 - 4} }$

$\bold{\implies \frac{x}{25} = \frac{y}{25} = \frac{1}{1}}$

$\bold{\implies \: x = 25 \: \: and \: y = 25}$

hence, there are 25 coins of each kind..