a man has only 20 paisa coins and 25 paisa coins. If he has 50 coins in all, which total up-to rupees 11.25 , how many coins of each kind does he have?
Answers
Answered by
2
Answer:
25
Step-by-step explanation:
Let no. of 20 paise coins is x and no. of 25 paise coins is y. Then by the given question,
x+y=50 --------------------(1) and
20x+25y=1125 [∵, Rs. 11.25=1125 paise]
or, 4x+5y=225 -----------(2)
Multiplying (1) with 4 we get,
4x+4y=200 ---------------(3)
Subtracting (3) from (2) we get,
y=25
Putting in (1)
x=50-y=50-25=25
∴, x=25, y=25
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Answered by
43
Let the number of 20 paisa coins be x and that of 25 paisa coins be y. then,
total value of 20 paisa coins = 20x paisa
total value of 25 paisa coins = 25y paisa
now by using corss-multiplication, we have
hence, there are 25 coins of each kind..
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