Math, asked by rishavkumarac, 11 months ago

a man has only 20 paisa coins and 25 paisa coins. If he has 50 coins in all, which total up-to rupees 11.25 , how many coins of each kind does he have?

Answers

Answered by muhammedinaz5473
2

Answer:

25

Step-by-step explanation:

Let no. of 20 paise coins is x and no. of 25 paise coins is y. Then by the given question,

x+y=50 --------------------(1) and

20x+25y=1125 [∵, Rs. 11.25=1125 paise]

or, 4x+5y=225 -----------(2)

Multiplying (1) with 4 we get,

4x+4y=200 ---------------(3)

Subtracting (3) from (2) we get,

y=25

Putting in (1)

x=50-y=50-25=25

∴, x=25, y=25

PLS mark me as BRAINLIEST

Answered by vanshikavikal448
43

 \bold \color{green} { \underline { \underline \red{  \green\star \: required \: answer}}} \star

Let the number of 20 paisa coins be x and that of 25 paisa coins be y. then,

 \bold{x + y = 50}

total value of 20 paisa coins = 20x paisa

total value of 25 paisa coins = 25y paisa

 \bold{so \: that \:  \: 20x + 25y = 1125 }\\  \bold{ \implies4x + 5y  - 225 = 0}

now by using corss-multiplication, we have

  \bold{\frac{x}{ - 225 + 150}  =  \frac{ - y}{ - 225 + 20}  =  \frac{1}{5 - 4} }

  \bold{\implies \frac{x}{25}  =  \frac{y}{25}  =  \frac{1}{1}}

  \bold{\implies \: x = 25 \:  \: and \: y = 25}

hence, there are 25 coins of each kind..

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