A man in balloon Rises vertically with an acceleration of 4.9 metre per square second release the ball 2 seconds after the balloon Rises from the ground the greatest height above the ground reaches by ball is
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hey mate!!
given=
• acceleration = 4•9 m/ sec^2
• initial velocity= 0 m/ sec
• time= 2 sec
ATQ= height = distance travelled
•s= ut+ 1/2* at^2
s= 0×2+1/2×4•9×2×2
s= 0+4•9
S= 4•9
hence height= 4•9 m
hope it works !!! plzz mark me brainlist.
given=
• acceleration = 4•9 m/ sec^2
• initial velocity= 0 m/ sec
• time= 2 sec
ATQ= height = distance travelled
•s= ut+ 1/2* at^2
s= 0×2+1/2×4•9×2×2
s= 0+4•9
S= 4•9
hence height= 4•9 m
hope it works !!! plzz mark me brainlist.
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