A man is 24 years older than his son 12 years ago he was five times as old as his son Find the number
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Answered by
1
let man's age be x
his son's be y
according to given condition
x=y+24..........eq i
according to second condition
(x-12)=5(y-12)
x-12= 5y-60
x-12+60=5y
x+48=5y
now from eq i
(y+24)+48=5y
y+24+48=5y
24+48=5y-y
72=4y
y=18
x=y+24
x=18+24=42
his son's be y
according to given condition
x=y+24..........eq i
according to second condition
(x-12)=5(y-12)
x-12= 5y-60
x-12+60=5y
x+48=5y
now from eq i
(y+24)+48=5y
y+24+48=5y
24+48=5y-y
72=4y
y=18
x=y+24
x=18+24=42
Answered by
1
Let the present age of the son be 'x'
So, his father age = x + 24
12 yrs ago,
Son's age = x - 12
Fathers age = (x + 24) - 12
= x + 12
Given,
5(x -12) = x + 12
5x - 60 = x + 12
4x = 72
x = 72/4 = 18
So, the son's present age = 18 yrs
And, fathers present age = 18 + 24 = 42 yrs
So, his father age = x + 24
12 yrs ago,
Son's age = x - 12
Fathers age = (x + 24) - 12
= x + 12
Given,
5(x -12) = x + 12
5x - 60 = x + 12
4x = 72
x = 72/4 = 18
So, the son's present age = 18 yrs
And, fathers present age = 18 + 24 = 42 yrs
shanikhan:
X - Son's current age X +24 = father's current age X + 24 - 12= 5( X -12) X + 12 = 5X - 60 4X = 72 X = 18 / Son's age 18 + 24 = 42 / father's age
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