Question

A man is 4 times as old as his son. After 16 years, he will be only twice as old as his son. The present age of man is​

Answer 1

Answer:

Son’s present age = x

Ajay’s age = 4 times (Son’s age)

y = 4x ———-> Equation (1)

After 16 years

Ajay’s age = y + 16

Son’s age = x + 16

Ajay’s age = 2 times (Son’s age)

y + 16 = 2 * (x + 16)

y + 16 = 2x + 32

y = 2x + 32 - 16

y = 2x + 16

According to equation (1) y = 4x, so

4x = 2x + 16

4x - 2x = 16

2x = 16

x = 8

Son’s present age = x = 8

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