A man is standing on the edge of a 20.0m high cliff. he throws a rock vertically upwards with an initial velocity of 10.0m/s.a) how high does the rock go?b) how long does it take to reach its maximum height?
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V1= 10m/s
g=10 m/s²
and
max height= h= V1²/2g
so,
h= 10²/2 x 10
h=5m
Time taken = V2-V1/g
V2= 0
so,
g=-10m/s
g=10 m/s²
and
max height= h= V1²/2g
so,
h= 10²/2 x 10
h=5m
Time taken = V2-V1/g
V2= 0
so,
g=-10m/s
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