Math, asked by payalmalkeet, 6 months ago

a man is three time his son age. 10 year ago he was 5 times his son's age. find their age​

Answers

Answered by Anonymous
2

Step-by-step explanation:

Ten years ago he was five times his son's age. Find their present ages. present age of his son=x=20 years.

Answered by Buvanesh77
2

Step-by-step explanation:

Let The Son's Age Be x

Man's Age=3x

10 years ago,

Son' age=x-10

Man's age=5x-10

x-10=5x-10

x-5x=-10-10

-4x=-20

x=20÷4

=5

Son's Age=x=5 years

Man's Age=3x=3×5=15 years

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