a man is thrice as old as his son.five year ago the man was four times as old as his son..find their present ages
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Answered by
4
let the age of the son be x
then the age of man be 3x
before five years the age of son be y and the
age of man be 4y that i understood from this question
then the age of man be 3x
before five years the age of son be y and the
age of man be 4y that i understood from this question
Answered by
11
hello!
present age of son=x years
present age of man=3x years
5 years ago man's age=(3x-5) years
5 years ago son's age=(x-5) years
BTP,
3x-5=4(x-5)
=>3x-5=4x-20
=>-x= -15
=>x=15
Son's present age is 15 years.
Man's present age is 45 years.
hope it helps... :)
present age of son=x years
present age of man=3x years
5 years ago man's age=(3x-5) years
5 years ago son's age=(x-5) years
BTP,
3x-5=4(x-5)
=>3x-5=4x-20
=>-x= -15
=>x=15
Son's present age is 15 years.
Man's present age is 45 years.
hope it helps... :)
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