A man is twice as old as his son 12 years ago the man was thrice as old as his son find their present ages
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let the age of man be x and the age of his son be y
x=2y i)
x-12=3(y-12)
x-3y=-24 ii)
putting the vaue of x in ii)
2y-3y=-24
-y=-24
y=24
x=2(24)
x=48
hence the age of man is 48 and the age of son is 24
x=2y i)
x-12=3(y-12)
x-3y=-24 ii)
putting the vaue of x in ii)
2y-3y=-24
-y=-24
y=24
x=2(24)
x=48
hence the age of man is 48 and the age of son is 24
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