A man is twice as old as his son. Twelve years ago, the man was thrice as old as his son. Find their present ages.
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Step-by-step explanation:
Let the age of the son be x
(Given) the age of man is 2x ( two times of the age of the son)
12 years ago
(Given) the age of man = 2x-12
ATQ
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<=> 3(x-12) = 2x-12
<=> 3x-36 = 2x-12
<=> 3x-2x = 36-12
<=> x = 24
Therefore, the present age of the son is 24 years
And the present age of the man is =2x
=2 (24)
=48 years
Hope it will help you bye bye
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