Math, asked by ratna4singhpa1o0t, 1 year ago

A man is twice as old as his son. Twelve years ago, the man was thrice as old as his son. Find their present ages.

Answers

Answered by ayush806
51
Here is your answer hope it helps you
Attachments:
Answered by chandanmahakud41720
75

Answer:

Step-by-step explanation:

Let the age of the son be x

(Given) the age of man is 2x ( two times of the age of the son)

12 years ago

(Given) the age of man = 2x-12

ATQ

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<=> 3(x-12) = 2x-12

<=> 3x-36 = 2x-12

<=> 3x-2x = 36-12

<=> x = 24

Therefore, the present age of the son is 24 years

And the present age of the man is =2x

=2 (24)

=48 years

Hope it will help you bye bye

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