Question

A man is walking at the rate of 8kmph towards the foot of
A tower 60 mts high . When he is 80 mts from the foot of the tower , the rate at which he is approaching the top is

Answer 1

Answer:

Let distance between the tower and man be x

then

dt

dx

=4.5 km/hr=1.25 m/s

y

2

=120

2

+x

2

⟹y

dt

dy

=x

dt

dx

When x=50⟹y=130

dt

dy

=

y

x

dt

dx

=

13

5

×1.25=0.48 m/s

the rate at which the person is approaching the top of tower is 0.48 m/s

solution

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Step-by-step explanation:

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Answer 2

Answer:

3km per day he walks an run