A man jogs 190 metre in 48 second and another 250 m in62 second . Find his average speed in km/hr .
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Two trains are approaching each other with the speed of 25km/hr. and 30km/hr. respectively from two different stations A and B. When two trains will meet each other, the second train had covered 20 km more than the first train. What is the distance between A and B stations?
rosangiri28pfbc5r:
easy
Sorry ... By mistake i send this ans....
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Given
First
distance covered = 190m
time = 48sec
so velocity = 190/48 = 3.9583m/s
Second
distance covered = 250m
time taken = 62 sec
so velocity = 250/62 =4.0322m/s
Now ,
Average velocity =(3.9583+4.0322)/2 = 7.94/2 = 3.97 m/s nearly equals to 4m/s
Hope it helps you
First
distance covered = 190m
time = 48sec
so velocity = 190/48 = 3.9583m/s
Second
distance covered = 250m
time taken = 62 sec
so velocity = 250/62 =4.0322m/s
Now ,
Average velocity =(3.9583+4.0322)/2 = 7.94/2 = 3.97 m/s nearly equals to 4m/s
Hope it helps you
you have given ans in m/s bt the ans should be in km/hr
Yes the answer should be in km /hr
I have also given the ans for ur que bt its nt showing the is 14.375km/hr
Correct answer is 14.e km /hr
Correct answer is 14.4 km /hr
its one on the same
Yes.....
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