Physics, asked by medaniakhan, 1 year ago

A man leaves his house for a cycle ride.he comes back to his house after half an hour covering a distance of 1 km .what is the magnitude of average velocity of his ride ( in km/ hr)?

Answers

Answered by antareepray2

25

Magnitude of average velocity of his ride (in km/hr)

$= \frac{displace}{t} = \frac{0}{ \frac{1}{2} } \\ = 0$

The velocity is 0 km/hr as displacement is 0 for he again returned to the same place.

HOPE THIS COULD HELP!!!!

medaniakhan: R u sure it's right?!

antareepray2: Yah! It's of no doubt because in physics, velocity means displacement over a particular time interval. Here the man has again come to the same position and hence, the magnitude of velocity is 0. And remember that don't add the unit here as they have only asked to give the magnitude. HOPE THIS COULD HELP!!!!

medaniakhan: Oh thanks so much!

antareepray2: My pleasure....

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