a man on the top of a vertical Tower observe a car moving at uniform speed towards the tower. if it takes 12 minutes for the angle of depression to change from 30 degree to 45 degree how soon ,after this ,will the car reaches the tower? ( answer will be 16.38)
guys please help me...
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Let the speed of the car be x units/min. Then, DC = 12x
Let the height of the tower be h units.
We have: ACB = 45o and ADB = 30o
In right triangle ABC,
h = BC
In right triangle ABD,
Required time taken by the car to reach the tower
= 6(1.732 + 1)
= 16.392 minutes
anika100:
let me inform you that it's the question of class 10 chapter HEIGHT AND DISTANCE
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