A man purchased a cowband a calf for rs 1300. he sold the calf at a profit of 20% and the cow at a profit of 25%. in this way his total profit was 300/13%. find the cost price of cow.
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3
let price of cow = x, price of calf = y
(1) x + y = 1300
(2) x times 1.25 + y times 1.20 = (x+y) times ( 1 + 300/13)
leads to 1.25*x + 1.20*y=1600
solving these two equations gets the answer of x = 800
(1) x + y = 1300
(2) x times 1.25 + y times 1.20 = (x+y) times ( 1 + 300/13)
leads to 1.25*x + 1.20*y=1600
solving these two equations gets the answer of x = 800
Answered by
0
Answer:
800
Step-by-step explanation
Total Profit= 1300*300/1300= 300
Let x= the cow price and (1300-x)= the calf
x*25/100 + (1300-x)*20/100 = 300
or, x/4 - x/5 = 300 - 260
or, 5x - 4x = 40*20
x = 800 ans
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