Math, asked by Harini211, 1 year ago

a man's age is eight times his son's age. after 2 years,his age will be 6 times his son's age.what are their present ages

Answers

Answered by ers1
12
this is the right answer of your question
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Answered by madhumalathi05
10
Let the son's age be x
Fathers age = 8x
After 2 yrs,
Father's age = 6(x+2)
So 8x +2 = 6(x+2)
8x+2 = 6x+12
8x-6x = 12-2
2x = 10
x = 5
Son's present age = 5
Father's present age = 5*8 = 40
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