Math, asked by selfishgirl, 1 year ago

A man sells two articles at the same price. On one article he makes profit of 15℅ . Find the loss of 15℅. Find the loss℅ or gain℅ on the whole transaction.

Answers

Answered by rajeev378
28
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Here is your answer
Let the Selling price of both Articles is 100
Now
for first Article
SP = 100
Profit% = 15%

As we know the formula
CP = SP×100/(100+Profit%)
 =  \frac{100 \times 100}{100 + 15}  \\  \\  =  \frac{10000}{115}  \\  \\  = 86.95
For second Article
SP = 100
Loss % = 15%
As we know the formula

CP= SP × 100/(100- Loss%)
 =  \frac{100 \times 100}{100 - 15}  \\  \\  =  \frac{10000}{85}  \\  \\  = 117.65
Now
Total SP = 200
Total CP = 86.95 + 117.65
= 204.57

So there is LOSS in the total transaction
as CP IS MORE THAN SP

Loss = CP - SP
= 204.57 - 200
= 4.57

LOSS % = LOSS × 100/CP
 =  \frac{4.57 \times 100}{204.57}  \\  \\  = 2.2\%
Therefore Total Loss Percentage is 2.2%


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selfishgirl: Well ans is 2.25℅
Answered by MonarkSinghD
12
Hi friends
Here is your answer

I case
LET SP = 100
PROFIT = 15%
CP =
 =  \frac{100 \times 100}{100 + 15}  \\  = 86.96
II CASE
SP = 100
LOSS = 15%
CP =
 =  \frac{100 \times 100}{100 - 15}  \\  = 117.65

Now
Total SP = 200
Total CP = 117.96 + 86.96 = 204.61
Loss = 204.61 - 200 = 4.61

Loss% =
 =  \frac{4.61 \times 100}{204.61}  \\  = 2.25\%
So Total Loss % is 2.25%

Hope it helps you

@ MSD
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