A man Sold His flat . He invests half of the money received at a compound interest of 6% per annum and the other half at 10% per annum for 3 year . He will get rupees 630 504 after 3 year. At what price did he sell his flat.
Answers
Answer:
Let man sold his flat = x rupee
And
we know formula for compound interest , As :
Amount = P (1 + r100)t , Here
P = Principle amount ,
r = Rate of interest
And
t = Time in years
Given : He invested half of the money received at a compound interest of 6 % p.a and the other half at 10 % p.a for 3 years. He will get rupees 6305 04 after 3 years . , So we get
⇒x2(1 + 6100)3 + x2(1 + 10100)3 = 630504
⇒x2(1 + 350)3 + x2(1 + 110)3 = 630504
⇒x2(5350)3 + x2(1110)3 = 630504
⇒x2[(5350)3 + (1110)3 ] = 630504
⇒x2[(148877125000) + (13311000) ] = 630504
⇒x2[(148877 + 166375125000) ] = 630504
⇒x2[315252125000 ] = 630504
⇒157626x125000 = 630504
⇒157626x = 78813000000
⇒x = 78813000000157626
⇒x = 500000
So,
Man sold his flat At Rs 5,00,000 ( Ans ).
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