a man standing 10 metres away from the foot of a tree sees its top at an elevation of 40 °.His height is 1.7 metres.What is the length of the tree?
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Answer:
Let the height of tower be h
Let height of hill be x
tan60o=40x−1.75⇒3=40x−1.75
403=x−1.75
∴, height of hill x=71.03 m
tan50o=40x−h−1.75
1.19=4071.03−h−1.75
47.67=71.03−h−1.75
Height of towerh=21.1 m
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