A man stands in between two high raised building & blows a whistle.He hears two successive echos after 0.8 sec & 2.4sec
.Calculate the distance between the buildings .
(Speed of sound = 330 m/s)
Answer with full explanations .....
Anonymous:
plz make it quick ...
Answers
Answered by
13
we know ,
time taken in echo sound = 2 x distance of source from building /speed of sound
0.8 = 2 x distance of source from 1st building /330
330 x 0.8/2 = distance of source from 1st building
132 m= distance of source from 1st building.
in the same way ,
distance of source from 2nd building =330 x 1.2 = 396 m
now distance between buildings = distance of source from 2nd building + distance of source from qst building = 396 +132 =528 m
time taken in echo sound = 2 x distance of source from building /speed of sound
0.8 = 2 x distance of source from 1st building /330
330 x 0.8/2 = distance of source from 1st building
132 m= distance of source from 1st building.
in the same way ,
distance of source from 2nd building =330 x 1.2 = 396 m
now distance between buildings = distance of source from 2nd building + distance of source from qst building = 396 +132 =528 m
528 m
how I don't understand
Check Shubham's answer ....
oh sorry
plz edit the answer ...
hey, as the man is standing in between two buildings then ,. The distance between two buildings = Distance between the man and 1st building + distance between man and 2nd building
Good :)
yes I now understand dear
Thanx :)
thanks to you dear
Answered by
17
Let the distance between the man and the first building be x m
time = 0.8 sec
speed = 330 m/s
distance = 2x
Distance = speed × time
= 330×0.8
= 264 m
x = 132 m
Similarly let the distance between the man and the 2nd building be y m
time = 2.4 sec
Speed = 330 m/s
Distance = 2y
Distance = speed × time
= 330 × 2.4
= 792 m
y = 396 m
--------------------------------------------------
Therefore the distance between the two buildings = x+y
= 132 + 396
= 528 m
===============================
time = 0.8 sec
speed = 330 m/s
distance = 2x
Distance = speed × time
= 330×0.8
= 264 m
x = 132 m
Similarly let the distance between the man and the 2nd building be y m
time = 2.4 sec
Speed = 330 m/s
Distance = 2y
Distance = speed × time
= 330 × 2.4
= 792 m
y = 396 m
--------------------------------------------------
Therefore the distance between the two buildings = x+y
= 132 + 396
= 528 m
===============================
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