Question

A man starts his journey from rest and gains a velocity of 10 m/s in 2 s. His acceleration is 1 m s -2 2 ms -2 5 ms -2 10 ms -2

Answer 1

Answer:

$\boxed{\mathfrak{Acceleration \ (a) = 5 \ ms^{-2}}}$

Given:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time taken (t) = 2 s

To Find:

Acceleration (a)

Explanation:

$\sf From \ 1^{st} \ equation \ of \ motion: \\ \boxed{ \bold{v = u + at}}$

Substituting value of v, u & t in the equation:

$\sf \implies 10 = 0 + a(2) \\ \\ \sf \implies 10 = 2a \\ \\ \sf \implies 2a = 10 \\ \\ \sf \implies a = \frac{10}{2} \\ \\ \sf \implies a = 5 \: m/s^2$

$\therefore$

Acceleration (a) = 5 m/s²

Answer 2

Answer:

v = 10 m/s

u = 0 m/s

t = 2s

v = u + at

10 = 0 + 2a

a = 10/2

a = 5 m/s²