Question

A man starts running with constant speed along a circular path of radius √2 m he complete two rounds in 16s the magnitude of the average velocity in firs 2s is

Answer 1

Answer:

16s/2s=8s

8 m per second

Answer 2

Given that,

Radius = √2 m

Number of round = 2

Time = 16 sec

He completed two rounds in 16s then

We need to calculate the angular velocity

Using formula of angular velocity

$\omega=2\pi f$

$\omega=\dfrac{2\times2\pi}{t}$

Put the value into the formula

$\omega=\dfrac{4\pi}{16}$

$\omega=\dfrac{\pi}{4}$

We need to calculate the angular displacement in 2 sec

Using formula of displacement

$\theta=\omega\times t$

Put the value into the formula

$\theta=\dfrac{\pi}{4}\times2$

$\theta=\dfrac{\pi}{2}$

So, the displacement is 2 m

We need to calculate the average velocity in 2 sec

Using formula of average velocity

$v=\dfrac{d}{t}$

Put the value into the formula

$v=\dfrac{2}{2}$

$v=1\ m/s$

Hence, The average velocity is 1 m/s.