Question

A man throws a ball to a maximum horizontal distance of 60m,maximum height reached is​

Answer 1

Answer:

maximumrange=

g

u

2

maximumheight=

2g

u

2

maximumrangeisgivenso..

80=

g

u

2

takngg=10msec

−2

u

2

=800

nowputu

2

inmaximumheightformulaso

max.height=

2g

u

2

=

20

800

max.height=40m

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