A man travelled one-third of a distance by bus, two-fifth by a taxi and the remaining 28km on scooter. How much distance did he travel ?
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Answer:
105
Step-by-step explanation:
Let x be the total distance
x/3 + 2x/5 + 28 = x
LCM of 3 and 5 = 15
(5x +6x)/15 + 28 = x
11x/15 + 28 = x
28 = x - 11x/15
28 = (15x-11x)/15
28 = 4x/15
28*15 = 4x
(28*15)/4 = x
420/4 = x
105 = x
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