A man walked 9 km towards east and then 12 km towards south.how far is he from starting point
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Answered by
0
in this problem you use
Pythagoras theorems
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9^2 + 12^2 = X^2
81 + 144 = X^2
= 225 = X^2
X = √225
X = 15 km
he is now at 15 km of starting point
Pythagoras theorems
------------------
|
|
|
|
9^2 + 12^2 = X^2
81 + 144 = X^2
= 225 = X^2
X = √225
X = 15 km
he is now at 15 km of starting point
Answered by
3
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By walking east and then south, the man would have formed a right angle trIangle with the starting point.
We will use Pythagoras' Theorem to find diagonal distance from the start point to the end point.
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a² + b² = c²
c² = 9² + 12²
c² = 225
c = √225
c = 15 km
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Answer: He is 15 km from the starting point.
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