Question

A man walks 20 km towards south and then 15 km towards east how far is he from his initial position

Answer 1

25 km, he is far from his initial position.

Given:

A man walks 20 km towards South direction and 15 km towards East direction.

To find:

How far is he from his initial position = ?

Solution:

Let us represent the given data in the form of a figure as attached below:-

From the figure, a man started at A traveled 20 km towards South to B, then 15 km towards East to C.

Now we need to find the distance from C to A (initial position)

Let AC $=x km$

From the Pythagoras theorem,

$\begin{array}{l}{A C^{2}=A B^{2}+B C^{2}} \\ {\Rightarrow x^{2}=20^{2}+15^{2}} \\ {\Rightarrow x^{2}=400+225} \\ {\Rightarrow x^{2}=625} \\ {\Rightarrow x=25}\end{array}$

Therefore,the man is 25 km from his initial point.  

Answer 2

....pls refer to the attachment