A mans age is 7 times more than his son. After 2 years, he becomes 6 times as old as his son. Find the age of the father
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Son Man
x 7x
After 2 yrs
Man's age =7x+2
Son's age =x+2
According to the problem:7x+2=6(x+2)
7x+2=6x+12
7x-6x=12-2
x=10
Son's age =10 yrs
Man's age = 7x=7*10=70 yrs
To check after two yrs man's age would be 72. Son's age would be 12 yrs
And 72/12=6(6 times)
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