a marble is projected with a velocity of 10m/s on a smooth incline as shown in figure . find the velocity after 2 sec
rratrey:
There is no figure. Wont be able to answer without that.
Where's the figure?
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V = u+at
So since the acceleration in this case gravity is always acting downwards we need to apply the above equation for only one component of velocity that is the one that's acting downwards.
V downward = [ 10*(1/√2) ] 2 + 10*2
= 10 [ √2 + 2 ]
Magnitude of v = √ [ (10/√2)^2 + ( 10 (√2+2))^2 ]
So since the acceleration in this case gravity is always acting downwards we need to apply the above equation for only one component of velocity that is the one that's acting downwards.
V downward = [ 10*(1/√2) ] 2 + 10*2
= 10 [ √2 + 2 ]
Magnitude of v = √ [ (10/√2)^2 + ( 10 (√2+2))^2 ]
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