Question

in a circle, O is a centre and AB is a chord and OP is perpendicular to AB and angle OPA and angle OPB = 90 degree(given). prove that AP = BP

Answer 1

In Triangle OLA and Triangle OLB

1)OA=OB(Radii of the same circle)

2)angleOLA=angleOLB(given)

3)OL=OL(Common)

Therefore   Triangle OLA is similar to Triangle  OLB

So PA=PB