A mass of 2 kg falls from a height of 40cm on a spring of for force constant 1960n/m.the spring is compressed by?
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Suppose h is the height from which the
mass m falls on the spring of force
constant K and x is the compression in
the spring.
The
Gain in elastic potential energy of spring
=Loss in gravitational potential energy of
falling mass
or
1
2
Kx
2
=mg (h+x)
1
2
×1960×
x
2
=2×9.8 (0.40 +x)
On solving we get
x=10cm
mass m falls on the spring of force
constant K and x is the compression in
the spring.
The
Gain in elastic potential energy of spring
=Loss in gravitational potential energy of
falling mass
or
1
2
Kx
2
=mg (h+x)
1
2
×1960×
x
2
=2×9.8 (0.40 +x)
On solving we get
x=10cm
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