Math, asked by SecondarySchoolWork, 11 months ago

A math question for you (shape) (10pts and question in attachments)

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Answers

Answered by sb93
2

Step-by-step explanation:

Area of rectangle :

\implies  A=l×b

\implies A=12×5

\implies \boxed{Area=60cm^{2}}

Area of Triangle :

h = 4cm (13-5 = 8/2 = 4cm)

b = 12cm

\implies A={\Large\frac{1}{2}}×b×h

\implies A={\Large\frac{1}{2}}×12×4

\implies \boxed{Area=24cm^{2}}

Area of hexagon = A of + A of + A of rectangle

Area of hexagon = 24+24+60

\large\boxed{Area\:of\:hexagon=108\:cm^{2} }

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Answered by Nivzegenius
2

Answer:

The answer is 108cm square

Step-by-step explanation:

The area of the hexagon is = the area of rectangle + area of 2 triangles.

area of rectangle = length x breadth = 12 x 5 = 60cm square

area of 2 triangles = base x height (as the 1 by 2 and 2 get cancelled).

=  12 x 4 =48 (height is 4 because the total height is 13. height of the 2 triangles is 13-5 = 8. height of 1 triangle is 8 by 2 which is 4.)

so the area of hexagon is = 60 + 48 = 108cm square.

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