A mechanic strikes a nail with a hammer of mass 0.5 kg moving with a velocity of 20m/s. The hammer comes to rest in 0.02 second after striking the nail. Calculate the force exerted by the hammer on the nail.
ojaswi7:
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m=0.5kg
u=20m/s
v=0m/s
t=0.02s
a=(v-u)/t
=-20/0.02
=-1000m/s2
F=ma
=0.5*(-1000)
-500
Therefore, the force exerted by the hammer on the nail is -500N.
u=20m/s
v=0m/s
t=0.02s
a=(v-u)/t
=-20/0.02
=-1000m/s2
F=ma
=0.5*(-1000)
-500
Therefore, the force exerted by the hammer on the nail is -500N.
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