A median of triangle divides the triangle into two triangles of equal areas. verify this result for tirangle ABC. whose vertices are A(4,-6) B(3,-2) & C(5,2)
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AnD is midpoint of BC
D= (3+5/2) (-2+2/2)= (4,0)
Area of ABD
=1/2 I4(-2-0) +3(0+6) +4(-6+2)I
=1/2 I-8+18-16I
=1/2 I-6I= 3
area of ADC
=1/2 I4(2-0) + 5(0+6) +4(-6-2)
=1/2 I8+ 30 -32I
=1/2 I6I= 3
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