a men travel 600 km by train and rest by car it takes 6.5 hour but if each travel 200 km by train and rest by car it takes 7hours find the speed of car and train
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Let x = speed of train
Let y = speed of car
speed = distance / time
time = distance / speed
6 hours 30 minutes = 6.5 hours <== 400 km by train ; 200 km by car
1/2 hour longer = 7 hours <== 200 km by train ; 400 km by car
Train time + car time = total time
400 / x + 200 / y = 6.5 <== two equations and two unknowns
200 / x + 400 / y = 7 . . . . . . solve for x and y
400y + 200x = 6.5 xy
200y + 400x = 7 xy
400y - 6.5 xy = - 200x
200y - 7xy = - 400x
y ( 400 - 6.5x) = -200x
y ( 200 - 7x) = -400x
y (6.5x - 400) = 200x
y (7x - 200) = 400x
y = 200x / (6.5x - 400)
y = 400x / (7x - 200) *
. . . since both equal y, the difference is zero
200x / (6.5x - 400) - 400x / (7x - 200) = 0
200x ( 7x - 200) - 400x (6.5x - 400) = 0
1400x^2 - 40000x - 2600x^2 + 160000x = 0
120000 x - 1200 x^2 = 0
100 - x = 0
x = 100 km / h = train speed
y = 400x / (7x - 200) . from *
y = 400 * 100 / (7 * 100 - 200)
y = 80 km / h = car speed
Let y = speed of car
speed = distance / time
time = distance / speed
6 hours 30 minutes = 6.5 hours <== 400 km by train ; 200 km by car
1/2 hour longer = 7 hours <== 200 km by train ; 400 km by car
Train time + car time = total time
400 / x + 200 / y = 6.5 <== two equations and two unknowns
200 / x + 400 / y = 7 . . . . . . solve for x and y
400y + 200x = 6.5 xy
200y + 400x = 7 xy
400y - 6.5 xy = - 200x
200y - 7xy = - 400x
y ( 400 - 6.5x) = -200x
y ( 200 - 7x) = -400x
y (6.5x - 400) = 200x
y (7x - 200) = 400x
y = 200x / (6.5x - 400)
y = 400x / (7x - 200) *
. . . since both equal y, the difference is zero
200x / (6.5x - 400) - 400x / (7x - 200) = 0
200x ( 7x - 200) - 400x (6.5x - 400) = 0
1400x^2 - 40000x - 2600x^2 + 160000x = 0
120000 x - 1200 x^2 = 0
100 - x = 0
x = 100 km / h = train speed
y = 400x / (7x - 200) . from *
y = 400 * 100 / (7 * 100 - 200)
y = 80 km / h = car speed
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