Physics, asked by Agent2890, 11 months ago

A mercury drop of radius 1.0 cm is sprayed into 10^(8) droplets of equal size. Calculate the energy expanded. (Surface tension of mercury = 32 xx 10^(-2) N//m).

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Answered by anjuyogeshyadav
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Answer:

A mercury drop of radius 1.0 cm is sprayed into 10^(8) droplets of equal size. Calculate the energy expanded. (Surface tension of mercury = 32 xx 10^(-2) N//m).

A mercury drop of radius 1.0 cm is sprayed into 10^(8) droplets of equal size. Calculate the energy expanded. (Surface tension of mercury = 32 xx 10^(-2) N//m).

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