Question

A mercury drop of radius 1 cm is broken into 10^6 droplets of equal size. The work done is (T=35xx10^-2(N)/(m))

Answer 1

Answer:

Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F * d). A force of 10 newtons, that moves an object 3 meters, does 30 n-m of work.