A metal atomic mass = 50 has a bcc crystal structure . The density of metal is 5.96 g/cmcube . Find the volume of unit cell ?
Answers
Answered by
42
M=50gmol−1
z=2
d=5.91gcm−3
V=a3
NA=6.023×10^23
d=z×M/NA×a3
a3=z×M/NA×d
=2×50/5.91×6.023×10 ^23
=2.809×10−23cm3
z=2
d=5.91gcm−3
V=a3
NA=6.023×10^23
d=z×M/NA×a3
a3=z×M/NA×d
=2×50/5.91×6.023×10 ^23
=2.809×10−23cm3
Answered by
35
Hey here is your answer
Atomic mass of metal=50 kg
BCC unit cell ,z =2
density of metal =5.96g/cm³
therefore,
volume of unit :-
a³=M×Z/Na×d
= 50×2/6.02×10²³×5.96
= 2.787 ×10-²³
Atomic mass of metal=50 kg
BCC unit cell ,z =2
density of metal =5.96g/cm³
therefore,
volume of unit :-
a³=M×Z/Na×d
= 50×2/6.02×10²³×5.96
= 2.787 ×10-²³
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