Question

a metal forms to oxide dioxide contain 80% metal 0.72 gram of lower oxide gave 0.8 gram of higher oxides when oxidized then the ratio of the weight of oxygen that combine with the fix weight of the metals in two oxide will be

Answer 1

In higher oxide

 

Wt of metal= 0.8x80/100=0.64g

 

Wt. Of oxygen=0.8-0.64=0.16g

 

In lower Oxide

 

Wt. of metal will remain the same as in higher oxide=0.64g

wt. of oxygen =0.72-0.64=0.08g

 

The ratio of weight of oxygen which combines with a fixed weight of metal in two oxides is

 

0.16:0.08

2:1

As it is a whole number ratio . The law of multiple proportion is illustrated.