a metal oxide has formula Al2O3. it can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6mg of hydrogen for complete reduction. what is the atomic weight of metal?
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Answer:
Z2
O
3
+3H
2
(g)→2Z+3H
2
O
∴6gH
2
gives mole Z
∴6×10
−3
gH
2
will give 0.002 mole Z
Number of moles =
Molarmass
Mass
0.002=
Molarmass
0.1596
∴ Molar mass =
0.002
0.1596
=79.8gmol
−1
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