A metal weighting 6g formed diatomic oxide upon heating in presence of air. The oxide thus formed weighed 10g. Write the chemical name of the compound.
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Metal + Oxygen ----> Metal oxide
one equivalent weight of metal reacts with one equivalent weight of oxygen to form metal oxide.
Equivalent weight of oxygen [ oxide ion] = Molar mass of O2/ charge on oxygen=16 g mol ⁻¹ / 2 mol eq⁻¹=8 g eq⁻¹
Therefore M grams of metal reacts with 8 grams of oxygen to form metal oxide which will have 8 grams more than mass of metal M.
This 8 grams is 22% of Mx 22/100= 8 grams
M=100x8/22 =36.36
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