Question

A metallic spherical shell with 14cm external diameter has a mass of 57552 divided by 7g. Find the thickness of shell If density of metal is9g/cm cube

Answer 1

Solution:-

Mass of the spherical metallic shell = 1789 1/3 g
= 5368/3 g
Density = 7 g/cm³ 
Volume of the spherical metallic shell = Mass/density
⇒ 5368/7 ÷ 7
= 255.61 cm³
Now,
External diameter = 10 cm
So, external radius = 5 cm
Let the internal radius be 'r'
Now,
According to the question.
4/3π(R³ - r³) = 255.61 cm³
⇒ 5³ - r³ = (255.61*3)/(4*3.14)
⇒ 125 - r³ = 766.83/12.56
⇒ 125 - r³ = 61.05
⇒ r³ = 125 - 61.05
⇒ r³ = 63.95
⇒ r = ∛63.95
⇒ r = 3.9989 or 4 (Approx)
So, the thickness = 5 - 4 
= 1 cm
Answer.
3.8

Answer 2

after seeing the attachment here is the final step:

ANSWER :

thickness = R-r = 7-5 = 2cm

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