A metallic toy is in the form of a cone of radius 11cm and height 62cm mounted on a hemisphere of the same radius is melted and recast into a solid cube. Find the surface area of the cube thus formed.
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r = 11 cm
h = 62cm
vol of hem + vol of cone = vol of cube
1/3πr^2×h + 2/3πr^3 = a^3
1/3 × π × 121 × 62 + 2/3 × π × 1331 = a^3
π(7502 + 2662/3) = 10164π
10164 × 22/7 = a^3
a^3 = 31944cm^3
a = 31.72 cm
surface area of cube = 6a^2
= 6036.95 cm sq
h = 62cm
vol of hem + vol of cone = vol of cube
1/3πr^2×h + 2/3πr^3 = a^3
1/3 × π × 121 × 62 + 2/3 × π × 1331 = a^3
π(7502 + 2662/3) = 10164π
10164 × 22/7 = a^3
a^3 = 31944cm^3
a = 31.72 cm
surface area of cube = 6a^2
= 6036.95 cm sq
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Answer:
FINAL ANSWER IS 2904cm^2
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